Question on anisotropy of interfacial energy

dendritic solidification, eutectics, peritectics,....
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Feng
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anti_bot: 333

Question on anisotropy of interfacial energy

Post by Feng » Wed Apr 24, 2024 1:22 pm

Hello,
I have some questions on the anisotropy of interfacial energy when simulating the 2D dendrite growth.
In the manual book, Vol0_MICRESS_phenomenology, it is written “In order to include anisotropy into the model, both the interfacial energy  and the interface mobility  are assumed to be anisotropic. In 2 dimensions this can be accomplished by making these parameters dependant on the angle θ between the growth direction and the crystal orientation i.e. σ= σ(θ) and μ= μ(θ). For a simple cubic symmetry in 2D these functions could look like σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)).”
In the example a dri file of 2D simulation of dendrite for Al-Cu alloy, it is shown as:
# Type of interfacial energy definition between 0 (LIQUID) and 1 (AL-FCC) ?
# Options: constant temp_dependent
constant
# Interfacial energy between 0 (LIQUID) and 1 (AL-FCC) ? [J/cm**2]
# [max. value for num. interface stabilisation [J/cm**2]]
1.6E-05 1.60000E-04
# Type of mobility definition between LIQUID and AL-FCC?
# Options: constant temp_dependent dg_dependent [fixed_minimum]
constant
# Kinetic coefficient mu between LIQUID and AL-FCC [cm**4/(Js)] ?
10.
# Is interaction isotropic?
# Options: isotropic
# anisotropic [junction_force] [harmonic_expansion]
anisotropic
# Anisotropy of interfacial stiffness? (cubic)
# 1 - delta * cos(4*phi), (delta =delta_stiffness =15*delta_energy)
# Coefficient delta (<1.) ?
0.4500000000000
# Anisotropy of interfacial mobility? (cubic)
# 1 + delta * cos(4*phi)
# Coefficient delta (<1.) ?
6.0000000000000E-02

The first question is the if “σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)) ” should be written as “σ= σ0 (1-γcos(4 θ)) and μ= μ0 (1-γcos(4 θ)) ”?
The second question is that is the “-” should be “+” in above equation, such as σ= σ0 (1-γcos(4 θ)) and μ= μ0 (1-γcos(4 θ)) should be σ= σ0 (1+γcos(4 θ)) and μ= μ0 (1+γcos(4 θ))? because I found these equations are different from some published papers, which makes me a little confused. or is there any special definition in Micress? I did not find any further information in the manual books of Micress.
In addition, is the interfacial energy, i.e. 1.6E-05, in the dri file the σ0 in σ= σ0 (1+γcos(4 θ))?
Many thanks.

Feng
Posts: 10
Joined: Thu Nov 28, 2013 10:52 am
anti_bot: 333

Re: Question on anisotropy of interfacial energy

Post by Feng » Tue Apr 30, 2024 10:06 am

Sorry, the first question is the if “σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)) ” should be written as “σ= σ0 (1+γcos(4 θ)) and μ= μ0 (1+γcos(4 θ)) ”?

Bernd
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Joined: Mon Jun 23, 2008 9:29 pm

Re: Question on anisotropy of interfacial energy

Post by Bernd » Fri May 03, 2024 9:37 pm

Dear Feng,

Please excuse my late reply, it seems that the notification function is not working correctly at our side. :(

What you refer to is from the old Manual which has not been updated since MICRESS version 6.4. You are right that it is not correct what has been written there.

Please note that the current MICRESS Manual is an online source which you can access via the MICRESS webpage under Dokumentation. Then you find the correct functions under MICRESS/MICRESS/Topics/Phase Interactions in Table 2, or by using the search function. For cubic symmetry and 2D-equivalent the anisotropy functions are:

σ=σ0*(1-δσcos(4Θ)
μ=μ0*(1+δμcos(4Θ)

Sorry for the confusion!

Bernd

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