Question on anisotropy of interfacial energy
Question on anisotropy of interfacial energy
Hello,
I have some questions on the anisotropy of interfacial energy when simulating the 2D dendrite growth.
In the manual book, Vol0_MICRESS_phenomenology, it is written “In order to include anisotropy into the model, both the interfacial energy and the interface mobility are assumed to be anisotropic. In 2 dimensions this can be accomplished by making these parameters dependant on the angle θ between the growth direction and the crystal orientation i.e. σ= σ(θ) and μ= μ(θ). For a simple cubic symmetry in 2D these functions could look like σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)).”
In the example a dri file of 2D simulation of dendrite for Al-Cu alloy, it is shown as:
# Type of interfacial energy definition between 0 (LIQUID) and 1 (AL-FCC) ?
# Options: constant temp_dependent
constant
# Interfacial energy between 0 (LIQUID) and 1 (AL-FCC) ? [J/cm**2]
# [max. value for num. interface stabilisation [J/cm**2]]
1.6E-05 1.60000E-04
# Type of mobility definition between LIQUID and AL-FCC?
# Options: constant temp_dependent dg_dependent [fixed_minimum]
constant
# Kinetic coefficient mu between LIQUID and AL-FCC [cm**4/(Js)] ?
10.
# Is interaction isotropic?
# Options: isotropic
# anisotropic [junction_force] [harmonic_expansion]
anisotropic
# Anisotropy of interfacial stiffness? (cubic)
# 1 - delta * cos(4*phi), (delta =delta_stiffness =15*delta_energy)
# Coefficient delta (<1.) ?
0.4500000000000
# Anisotropy of interfacial mobility? (cubic)
# 1 + delta * cos(4*phi)
# Coefficient delta (<1.) ?
6.0000000000000E-02
The first question is the if “σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)) ” should be written as “σ= σ0 (1-γcos(4 θ)) and μ= μ0 (1-γcos(4 θ)) ”?
The second question is that is the “-” should be “+” in above equation, such as σ= σ0 (1-γcos(4 θ)) and μ= μ0 (1-γcos(4 θ)) should be σ= σ0 (1+γcos(4 θ)) and μ= μ0 (1+γcos(4 θ))? because I found these equations are different from some published papers, which makes me a little confused. or is there any special definition in Micress? I did not find any further information in the manual books of Micress.
In addition, is the interfacial energy, i.e. 1.6E-05, in the dri file the σ0 in σ= σ0 (1+γcos(4 θ))?
Many thanks.
I have some questions on the anisotropy of interfacial energy when simulating the 2D dendrite growth.
In the manual book, Vol0_MICRESS_phenomenology, it is written “In order to include anisotropy into the model, both the interfacial energy and the interface mobility are assumed to be anisotropic. In 2 dimensions this can be accomplished by making these parameters dependant on the angle θ between the growth direction and the crystal orientation i.e. σ= σ(θ) and μ= μ(θ). For a simple cubic symmetry in 2D these functions could look like σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)).”
In the example a dri file of 2D simulation of dendrite for Al-Cu alloy, it is shown as:
# Type of interfacial energy definition between 0 (LIQUID) and 1 (AL-FCC) ?
# Options: constant temp_dependent
constant
# Interfacial energy between 0 (LIQUID) and 1 (AL-FCC) ? [J/cm**2]
# [max. value for num. interface stabilisation [J/cm**2]]
1.6E-05 1.60000E-04
# Type of mobility definition between LIQUID and AL-FCC?
# Options: constant temp_dependent dg_dependent [fixed_minimum]
constant
# Kinetic coefficient mu between LIQUID and AL-FCC [cm**4/(Js)] ?
10.
# Is interaction isotropic?
# Options: isotropic
# anisotropic [junction_force] [harmonic_expansion]
anisotropic
# Anisotropy of interfacial stiffness? (cubic)
# 1 - delta * cos(4*phi), (delta =delta_stiffness =15*delta_energy)
# Coefficient delta (<1.) ?
0.4500000000000
# Anisotropy of interfacial mobility? (cubic)
# 1 + delta * cos(4*phi)
# Coefficient delta (<1.) ?
6.0000000000000E-02
The first question is the if “σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)) ” should be written as “σ= σ0 (1-γcos(4 θ)) and μ= μ0 (1-γcos(4 θ)) ”?
The second question is that is the “-” should be “+” in above equation, such as σ= σ0 (1-γcos(4 θ)) and μ= μ0 (1-γcos(4 θ)) should be σ= σ0 (1+γcos(4 θ)) and μ= μ0 (1+γcos(4 θ))? because I found these equations are different from some published papers, which makes me a little confused. or is there any special definition in Micress? I did not find any further information in the manual books of Micress.
In addition, is the interfacial energy, i.e. 1.6E-05, in the dri file the σ0 in σ= σ0 (1+γcos(4 θ))?
Many thanks.
Re: Question on anisotropy of interfacial energy
Sorry, the first question is the if “σ= σ0 (1-cos(4 θ)) and μ= μ0 (1-cos(4 θ)) ” should be written as “σ= σ0 (1+γcos(4 θ)) and μ= μ0 (1+γcos(4 θ)) ”?
Re: Question on anisotropy of interfacial energy
Dear Feng,
Please excuse my late reply, it seems that the notification function is not working correctly at our side.
What you refer to is from the old Manual which has not been updated since MICRESS version 6.4. You are right that it is not correct what has been written there.
Please note that the current MICRESS Manual is an online source which you can access via the MICRESS webpage under Dokumentation. Then you find the correct functions under MICRESS/MICRESS/Topics/Phase Interactions in Table 2, or by using the search function. For cubic symmetry and 2D-equivalent the anisotropy functions are:
σ=σ0*(1-δσcos(4Θ)
μ=μ0*(1+δμcos(4Θ)
Sorry for the confusion!
Bernd
Please excuse my late reply, it seems that the notification function is not working correctly at our side.
What you refer to is from the old Manual which has not been updated since MICRESS version 6.4. You are right that it is not correct what has been written there.
Please note that the current MICRESS Manual is an online source which you can access via the MICRESS webpage under Dokumentation. Then you find the correct functions under MICRESS/MICRESS/Topics/Phase Interactions in Table 2, or by using the search function. For cubic symmetry and 2D-equivalent the anisotropy functions are:
σ=σ0*(1-δσcos(4Θ)
μ=μ0*(1+δμcos(4Θ)
Sorry for the confusion!
Bernd
Re: Question on anisotropy of interfacial energy
Thanks a lot for your kind reply. As you have shown, for cubic symmetry and 2D-equivalent, the anisotropy stiffness function is σ=σ0*(1-δσcos(4Θ)). However, from some references, it is written σ=σ0*(1+δσcos(4Θ)), where Θ is the angle between n and a fixed reference axis. I also checked the book, titled A Phase-field model for technical alloy solidification, by Janin Eiken, where the anisotropy is also written as a(2D)=1+δσcos(4Θ). If the stiffness function is σ=σ0*(1-δσcos(4Θ)), is that meant the Θ here has a different reference axis from that mention above? what is the definition of Θ in the Micress for a cubic symmetry?
In addition, is the interfacial energy set in dri file is the σ0 in above equation?
In addition, is the interfacial energy set in dri file is the σ0 in above equation?
Re: Question on anisotropy of interfacial energy
Hi Feng,
It is important to distinguish between the interfacial ENERGY σ and the interfacial STIFFNESS σ*.
- The cubic 2D-anisotropy of the interfacial energy is σ = σ0 (1 + δ cos(4Θ)).
- The cubic 2D-anisotropy of the interfacial stiffness is σ*= σ0* (1- δ* cos(4Θ)).
From σ*= σ + σ'' we get σ0* = σ0 and δ* = 15 δ.
If you have selected the standard anisotropy model, σ0*=σ0 corresponds to the interfacial energy you have already specified in your driving file (i.e. 1.6E-05) and the anisotropy coefficient δ* corresponds to the anisotropy of the stiffness, which is 15 times the value of the anisotropy of the interfacial energy, usually given in the literature.
The different models are described in the manual:
https://docs.micress.rwth-aachen.de/7.2 ... mobilities.
The pragmatic use of the stiffness is described in "A Phase-field model for technical alloy solidification" on page 120.
With best regards,
Janin
It is important to distinguish between the interfacial ENERGY σ and the interfacial STIFFNESS σ*.
- The cubic 2D-anisotropy of the interfacial energy is σ = σ0 (1 + δ cos(4Θ)).
- The cubic 2D-anisotropy of the interfacial stiffness is σ*= σ0* (1- δ* cos(4Θ)).
From σ*= σ + σ'' we get σ0* = σ0 and δ* = 15 δ.
If you have selected the standard anisotropy model, σ0*=σ0 corresponds to the interfacial energy you have already specified in your driving file (i.e. 1.6E-05) and the anisotropy coefficient δ* corresponds to the anisotropy of the stiffness, which is 15 times the value of the anisotropy of the interfacial energy, usually given in the literature.
The different models are described in the manual:
https://docs.micress.rwth-aachen.de/7.2 ... mobilities.
The pragmatic use of the stiffness is described in "A Phase-field model for technical alloy solidification" on page 120.
With best regards,
Janin
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Re: Question on anisotropy of interfacial energy
Hello Janin,
It looks much clear. Thank you very much.
Kind regards,
Feng
It looks much clear. Thank you very much.
Kind regards,
Feng
Re: Question on anisotropy of interfacial energy
Hello Janin,
One more question, the kinetic coefficient μ between liquid and solid during solidification is set, for example, to 0.05. For anisotropy of interfacial mobility μ= μ0 (1-δμcos(4 θ)), is the μ0 corresponding to the previously specified 0.05? If I change the anisotropy of interfacial stiffness (δσ*) in the driving file from 0.5 to 0.05 for example, how to adjust δμ? is there any principle in the Micress to adjust δμ according to δσ*, or other parameters?
In addition, for 2D cubic symmetry, δσ* is the value between 0 and 1, that means the <100> directions have the largest interfacial energy, which are always the prefer growth direction. Is there any possible to adjust any parameters to make <110> directions as the prefer growth direction in 2D cubic symmetry? because some references have shown that in high Zn-containing Al alloys, the prefer growth direction of dendrite is <110>.
Many thanks,
Feng
One more question, the kinetic coefficient μ between liquid and solid during solidification is set, for example, to 0.05. For anisotropy of interfacial mobility μ= μ0 (1-δμcos(4 θ)), is the μ0 corresponding to the previously specified 0.05? If I change the anisotropy of interfacial stiffness (δσ*) in the driving file from 0.5 to 0.05 for example, how to adjust δμ? is there any principle in the Micress to adjust δμ according to δσ*, or other parameters?
In addition, for 2D cubic symmetry, δσ* is the value between 0 and 1, that means the <100> directions have the largest interfacial energy, which are always the prefer growth direction. Is there any possible to adjust any parameters to make <110> directions as the prefer growth direction in 2D cubic symmetry? because some references have shown that in high Zn-containing Al alloys, the prefer growth direction of dendrite is <110>.
Many thanks,
Feng
Re: Question on anisotropy of interfacial energy
Hello Feng,
1) Yes, μ0 corresponds to the previously specified mobility. However, to model diffusion controlled processes (e.g. dendritic solidification) it is recommended to set μ0 to a high value and let Micress automatically calculate the effective mobility and the anti-trapping currents in the thin interface limit. This is done by selecting 'phase_interaction' with the additional option 'redistribution_control' (and further below 'atc mob_corr'), see e.g. the training example T01_01_AlCu_E_Dendritic_2D_Lin.dri.
2) The kinetic anisotropy coefficient δμ is a material specific physical quantity, but it is difficult to find in the literature. You may find some values if you search for molecular dynamics simulations. As far as I know, delta = 0.05 is a typical value for metallic alloys.
3.) In 2D simulations, you can simply choose negative values for both δμ and δσ* to get preferential growth in 110 directions. In 3D, more complex functions can be specified using 'anisotropic' with the additional option 'harmonic_expansion'.
Have a nice weekend!
Janin
1) Yes, μ0 corresponds to the previously specified mobility. However, to model diffusion controlled processes (e.g. dendritic solidification) it is recommended to set μ0 to a high value and let Micress automatically calculate the effective mobility and the anti-trapping currents in the thin interface limit. This is done by selecting 'phase_interaction' with the additional option 'redistribution_control' (and further below 'atc mob_corr'), see e.g. the training example T01_01_AlCu_E_Dendritic_2D_Lin.dri.
2) The kinetic anisotropy coefficient δμ is a material specific physical quantity, but it is difficult to find in the literature. You may find some values if you search for molecular dynamics simulations. As far as I know, delta = 0.05 is a typical value for metallic alloys.
3.) In 2D simulations, you can simply choose negative values for both δμ and δσ* to get preferential growth in 110 directions. In 3D, more complex functions can be specified using 'anisotropic' with the additional option 'harmonic_expansion'.
Have a nice weekend!
Janin
Re: Question on anisotropy of interfacial energy
Hi Janin,
Many thanks for you kind reply. I will try to do some simulations according to your suggestions.
Kind regards,
Feng
Many thanks for you kind reply. I will try to do some simulations according to your suggestions.
Kind regards,
Feng